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Old 01-06-2008, 03:41 PM   #1
R0BD0G
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Default Math Problemo

i have a right angle triangle 6 x 6.2 x 8.8.
whats the rule for working it out??

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Old 01-06-2008, 03:45 PM   #2
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What are you trying to work out?
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Old 01-06-2008, 03:47 PM   #3
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thats what i thought it might be but wasnt sure. i thought pythag was usually used if you were missing the length of the hypotenuese
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Old 01-06-2008, 03:49 PM   #4
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what exactly are you trying to work out?
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Old 01-06-2008, 03:47 PM   #5
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what do you want to work out?
angles
sine = opposite/hypotenuse
cosine = ajacent/hypotenuse
tangent = opposite/ajacent

if you want to work the angles out from lengths you use the inverse sine/cosine/tangent buttons on the calculator, usually sin-1, cos-1 or tan-1 on the calculator

pythagerous' theroem
a squared + b squared = c squared
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Old 01-06-2008, 03:50 PM   #6
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area. sorry
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Old 01-06-2008, 03:50 PM   #7
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LOl good ole maths
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Old 01-06-2008, 03:54 PM   #8
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Could you calculate it like a rectangle/square and divide by 2. Length*width then divide by two? Two equal right angle triangles placed on each other would be a square or rectangle depending on triangle shape? Do you know what I mean?
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Old 01-06-2008, 05:49 PM   #9
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Quote:
Originally Posted by davonafairlane
Could you calculate it like a rectangle/square and divide by 2. Length*width then divide by two? Two equal right angle triangles placed on each other would be a square or rectangle depending on triangle shape? Do you know what I mean?
That only works for a right angle triangle...



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Old 01-06-2008, 06:13 PM   #10
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Quote:
Originally Posted by 4Vman
That only works for a right angle triangle...
yeah, he said he had a right angled triangle.
for non right angled triangle he would be using the sine area rule

area = 1/2 a x b sin c

where c is the angle between the 2 sides a and b
a and b are both lengths.
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Old 05-06-2008, 08:53 AM   #11
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Quote:
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yeah, he said he had a right angled triangle.
But, Alas, he does not
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Old 05-06-2008, 01:34 PM   #12
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Quote:
Originally Posted by EgoFG
But, Alas, he does not
bingo, those dimensions do not make a right angled triangle.

and the formula is 1/2 base x PERPENDICULAR height.
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Old 01-06-2008, 03:56 PM   #13
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ahh. makes sence dont it. thanks
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Old 01-06-2008, 04:01 PM   #14
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I did YR12 in 2004 I don't remember all the rules or anything strange like that but the logic makes sense, glad to help. Trigonometry was my favourite maths section though, sad as that may sound.

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Old 01-06-2008, 05:14 PM   #15
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Area of a triangle is A = 1/2BxH

ie. A - Area
B - Base
H - Height
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Old 01-06-2008, 05:14 PM   #16
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i do prevocational math a.....whats trigonometry
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Old 01-06-2008, 05:14 PM   #17
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1/2 base length X height for a right angle triangle area (1/2 a rectangle)
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Old 01-06-2008, 06:00 PM   #18
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Quote:
Originally Posted by Kermit 73
i have a right angle triangle 6 x 6.2 x 8.8.
whats the rule for working it out??
Quote:
Originally Posted by 4Vman
That only works for a right angle triangle...
: :
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Old 01-06-2008, 06:13 PM   #19
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Quote:
Originally Posted by BabyJ
: :
good point! :



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Old 01-06-2008, 06:16 PM   #20
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Quote:
Originally Posted by 4Vman
good point! :
Your welcome!
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Old 01-06-2008, 06:20 PM   #21
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The correct rule as mentioned already is BASE X HEIGHT divided by 2.

It works for ANY and ALL triangles, as long as the height measurement is at right angles to the base (but the triangle does not have to be a right angled triangle)
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Old 01-06-2008, 09:18 PM   #22
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Quote:
Originally Posted by Yellow_Festiva
The correct rule as mentioned already is BASE X HEIGHT divided by 2.

It works for ANY and ALL triangles, as long as the height measurement is at right angles to the base (but the triangle does not have to be a right angled triangle)
correctimondo!!!!

yeah you can use your sine rule for getting area, but why when you can do it so much simpler
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Old 02-06-2008, 07:59 AM   #23
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Just use a bigger hammer !!!!
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Old 02-06-2008, 11:46 PM   #24
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Half base X height...

Good old maths..fave topic at school...

I never reached any great heights (does it show), but I still enjoyed it

Still miss learning about maths too.
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Old 05-06-2008, 08:23 AM   #25
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Another complex triangle / mathematical problem that i solved recently


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Old 05-06-2008, 09:01 AM   #26
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Isn't this primary school maths?

Q. What is the area of a rectangle?
A. = Length x width

Q. What is a right angle triangle?
A. = 1/2 a rectangle
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Old 05-06-2008, 12:10 PM   #27
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I went well in maths till yr 10 then i gave it up, now i dont remember a thing!

I wish i kept it up now
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Old 05-06-2008, 12:23 PM   #28
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Q1.)
If BP 98 cost 169.9c/L and I own a mondern V8 with a 68L tank,

A) How much will it cost to fill from empty?
B) How many banks will knock me back for a loan to fill said tank?

Given you have found the answers to Q1 A&B;
Q2.) If one of my kindeys is worth $20,000 on the black market;

A) How many tanks of fuel will in buy?
B) Will K-Rudd's Butler manage to throw a 'Casey' style party at the PM's house
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Old 07-06-2008, 11:23 PM   #29
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Quote:
Originally Posted by DJL351
Q1.)
If BP 98 cost 169.9c/L and I own a mondern V8 with a 68L tank,

A) How much will it cost to fill from empty?
B) How many banks will knock me back for a loan to fill said tank?

Given you have found the answers to Q1 A&B;
Q2.) If one of my kindeys is worth $20,000 on the black market;

A) How many tanks of fuel will in buy?
B) Will K-Rudd's Butler manage to throw a 'Casey' style party at the PM's house


Well done!
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Old 05-06-2008, 12:46 PM   #30
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stop It I`m Getting A Head Ache !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!![u]
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